What is -1/2 (y+2)=(x+4)^2 ?

The solution to -1/2 (y+2)=(x+4)^2 is Parabola with (h,k)=(-4,-2),p=-1/8

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-1/2 (y+2)=(x+4)^2

- \frac{1}{2} (y + 2) = (x + 4)^{2}

(h, k) = (- 4, - 2), p = - \frac{1}{8}

Solution steps

- \frac{1}{2} (y + 2) = (x + 4)^{2}

Rewrite

- \frac{1}{2} (y + 2) = (x + 4)^{2}

in the standard form:

4 (- \frac{1}{8}) (y - (- 2)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 2), p = - \frac{1}{8}

3 x^{2} + 2 y = 10

y = - 3 (x + 1)^{2} + 5

2 x^{2} - 8 x - y + 5 = 0

x^{2} - 8 y = x

Y > - X^{2} - 3 X + 1

What is -1/2 (y+2)=(x+4)^2 ?
The solution to -1/2 (y+2)=(x+4)^2 is Parabola with (h,k)=(-4,-2),p=-1/8