What is yy-320=40(x-2010) ?

The solution to yy-320=40(x-2010) is Parabola with (h,k)=(2002,0),p=10

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yy-320=40(x-2010)

yy - 320 = 40 (x - 2010)

(h, k) = (2002, 0), p = 10

Solution steps

yy - 320 = 40 (x - 2010)

Rewrite

yy - 320 = 40 (x - 2010)

in the standard form:

4 \cdot 10 (x - 2002) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (2002, 0), p = 10

y^{2} + 4 y + 6 x - 5 = 0

x + 4 > y^{2}

x = a y^{2}

y = 1 (x - 1)^{2} + 0

y^{2} - x - 2 = 0

What is yy-320=40(x-2010) ?
The solution to yy-320=40(x-2010) is Parabola with (h,k)=(2002,0),p=10