What is (x-0)^2=4(9/8)(y-3) ?

The solution to (x-0)^2=4(9/8)(y-3) is Parabola with (h,k)=(0,3),p= 9/8

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(x-0)^2=4(9/8)(y-3)

(x - 0)^{2} = 4 (\frac{9}{8}) (y - 3)

(h, k) = (0, 3), p = \frac{9}{8}

Solution steps

(x - 0)^{2} = 4 \cdot \frac{9}{8} (y - 3)

Rewrite

(x - 0)^{2} = 4 \cdot \frac{9}{8} (y - 3)

in the standard form:

4 \cdot \frac{9}{8} (y - 3) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = \frac{9}{8}

(x + 4)^{2} = - 8 (y - 2)

(x - 6)^{2} = 12 (y - 1)

(y - 3)^{2} = - 8 (x - 4)

y^{2} - 2 y - 8 x + 17 = 0

y = - 4 x^{2} + 8 x - 8

What is (x-0)^2=4(9/8)(y-3) ?
The solution to (x-0)^2=4(9/8)(y-3) is Parabola with (h,k)=(0,3),p= 9/8