What is y^2+3x-16y+65=0 ?

The solution to y^2+3x-16y+65=0 is Parabola with (h,k)=(-1/3 ,8),p=-3/4

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y^2+3x-16y+65=0

y^{2} + 3 x - 16 y + 65 = 0

(h, k) = (- \frac{1}{3}, 8), p = - \frac{3}{4}

Solution steps

y^{2} + 3 x - 16 y + 65 = 0

Rewrite

y^{2} + 3 x - 16 y + 65 = 0

in the standard form

4 (- \frac{3}{4}) (x - (- \frac{1}{3})) = (y - 8)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{3}, 8), p = - \frac{3}{4}

3 x^{2} - 9 y - 5 y - 2 = 0

2 (x - 2)^{2} = 8 (7 + y)

(x - 5)^{2} = - 66 (y - 1)

x^{2} + 8 x - 2 y + 4 = 0

y + 10 = (x - 3)^{2}

What is y^2+3x-16y+65=0 ?
The solution to y^2+3x-16y+65=0 is Parabola with (h,k)=(-1/3 ,8),p=-3/4