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Popular >

y=(4x^2-1)+6

Solution

y = (4 x^{2} - 1) + 6

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 5

Y Intercepts : (0, 5)

Vertex : Minimum (0, 5)

Inverse : \frac{x - 5}{2}, - \frac{x - 5}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

4 x^{2} - 1 + 6 : - \infty < x < \infty

Range of

4 x^{2} - 1 + 6 : f (x) \geq 5

Axis interception points of

4 x^{2} - 1 + 6 :

Y Intercepts

: (0, 5)

Vertex of

4 x^{2} - 1 + 6 :

Minimum

(0, 5)

Inverse of

4 x^{2} - 1 + 6 : \frac{x - 5}{2}, - \frac{x - 5}{2}

Graph

Popular Examples

(x - 2)^{2} = 1 (y + 3)

(x - 1)^{2} = 8 (y + 2)

y^{2} + 6 x + 4 y + 5 = 0

(x-5)^2=24(y+1)

(x - 5)^{2} = 24 (y + 1)

(x - 3)^{2} = 8 (y - 0)

Frequently Asked Questions (FAQ)

What is the y=(4x^2-1)+6 ?
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