What is (y)^2=-2(x-5/2) ?

The solution to (y)^2=-2(x-5/2) is Parabola with (h,k)=(5/2 ,0),p=-1/2

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(y)^2=-2(x-5/2)

(y)^{2} = - 2 (x - \frac{5}{2})

(h, k) = (\frac{5}{2}, 0), p = - \frac{1}{2}

Solution steps

y^{2} = - 2 (x - \frac{5}{2})

Rewrite

y^{2} = - 2 (x - \frac{5}{2})

in the standard form:

4 (- \frac{1}{2}) (x - \frac{5}{2}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, 0), p = - \frac{1}{2}

x^{2} + 8 x - 24 y + 64 = 0

12 x^{2} + 3 x - 10 y - 1 = 0

y^{2} - 6 y - 8 x - 7 = 0

x^{2} + 2 x - 20 y + 41 = 0

f (x) = x^{2} - 2 x - 6 f (2) - f (t)

What is (y)^2=-2(x-5/2) ?
The solution to (y)^2=-2(x-5/2) is Parabola with (h,k)=(5/2 ,0),p=-1/2