What is (x+3/2)^2=4(y-2) ?

The solution to (x+3/2)^2=4(y-2) is Parabola with (h,k)=(-3/2 ,2),p=1

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(x+3/2)^2=4(y-2)

(x + \frac{3}{2})^{2} = 4 (y - 2)

(h, k) = (- \frac{3}{2}, 2), p = 1

Solution steps

(x + \frac{3}{2})^{2} = 4 (y - 2)

Rewrite

(x + \frac{3}{2})^{2} = 4 (y - 2)

in the standard form:

4 \cdot 1 \cdot (y - 2) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, 2), p = 1

x^{2} + 5 y = 10

\frac{( y + 1 )}{( x ^{2} + y - 2 )} = - 2

(x - 3)^{2} = - 3 (y - 2)

2 x = \frac{y ^{2}}{2}

y^{2} - 2 x + 2 y - 1 = 0

What is (x+3/2)^2=4(y-2) ?
The solution to (x+3/2)^2=4(y-2) is Parabola with (h,k)=(-3/2 ,2),p=1