What is -f(x)+4=2x^2-4x+1 ?

The solution to -f(x)+4=2x^2-4x+1 is Parabola with (h,k)=(1,5),p=-1/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-f(x)+4=2x^2-4x+1

- f (x) + 4 = 2 x^{2} - 4 x + 1

(h, k) = (1, 5), p = - \frac{1}{8}

Solution steps

- y + 4 = 2 x^{2} - 4 x + 1

Rewrite

- y + 4 = 2 x^{2} - 4 x + 1

in the standard form

4 (- \frac{1}{8}) (y - 5) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 5), p = - \frac{1}{8}

x^{2} - 4 x - 12 y - 56 = 0

y^{2} + 2 x - 2 y - 3 = 0

x \frac{2}{3} x - 5 y = 2

x^{(2)} + 2 y = 0

y \frac{y}{12.5} = 3.5 + x

What is -f(x)+4=2x^2-4x+1 ?
The solution to -f(x)+4=2x^2-4x+1 is Parabola with (h,k)=(1,5),p=-1/8