What is 4x^2-48x+y+148=0 ?

The solution to 4x^2-48x+y+148=0 is Parabola with (h,k)=(6,-4),p=-1/16

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4x^2-48x+y+148=0

4 x^{2} - 48 x + y + 148 = 0

(h, k) = (6, - 4), p = - \frac{1}{16}

Solution steps

4 x^{2} - 48 x + y + 148 = 0

Rewrite

4 x^{2} - 48 x + y + 148 = 0

in the standard form

4 (- \frac{1}{16}) (y - (- 4)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 4), p = - \frac{1}{16}

2 x^{2} - 6 x + 5 = 2 k (x) + k (x)

y = \frac{7}{4} x^{2}

2 x^{2} - x + 4 m (x) = 0

y = 6 x - 3 x^{2}

2 x^{2} + 8 y = 15

What is 4x^2-48x+y+148=0 ?
The solution to 4x^2-48x+y+148=0 is Parabola with (h,k)=(6,-4),p=-1/16