What is 1f(x)=2x^2+8x-24 ?

The solution to 1f(x)=2x^2+8x-24 is Parabola with (h,k)=(-2,-32),p= 1/8

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1f(x)=2x^2+8x-24

1 f (x) = 2 x^{2} + 8 x - 24

(h, k) = (- 2, - 32), p = \frac{1}{8}

Solution steps

1 \cdot y = 2 x^{2} + 8 x - 24

Rewrite

1 \cdot y = 2 x^{2} + 8 x - 24

in the standard form

4 \cdot \frac{1}{8} (y - (- 32)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 32), p = \frac{1}{8}

y^{2} + 12 x - 18 y = - 81

x^{2} - 6 x - 2 y + 11 = 0

(x - h) = 4 a (y - k)^{2}

x^{2} - 5 x + 4 - M \geq 0

x = y - 5.3 x^{2}

What is 1f(x)=2x^2+8x-24 ?
The solution to 1f(x)=2x^2+8x-24 is Parabola with (h,k)=(-2,-32),p= 1/8