What is 4x^2+5x+h(x)=0 ?

The solution to 4x^2+5x+h(x)=0 is Parabola with (h,k)=(-5/8 , 25/16),p=-1/16

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4x^2+5x+h(x)=0

4 x^{2} + 5 x + h (x) = 0

(h, k) = (- \frac{5}{8}, \frac{25}{16}), p = - \frac{1}{16}

Solution steps

4 x^{2} + 5 x + y = 0

Rewrite

4 x^{2} + 5 x + y = 0

in the standard form

4 (- \frac{1}{16}) (y - \frac{25}{16}) = (x - (- \frac{5}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{8}, \frac{25}{16}), p = - \frac{1}{16}

y^{2} - 4 y + 20 x + 4 = 0

10 x^{2} - 5 x = y + 4

f (x) (a - 9) = 2 x^{2} + 8

x = \frac{y ^{2}}{4} + 1

4 x^{2} - 8 x + 3 y - 2 = 0

What is 4x^2+5x+h(x)=0 ?
The solution to 4x^2+5x+h(x)=0 is Parabola with (h,k)=(-5/8 , 25/16),p=-1/16