What is 3x^2-13y+12=0 ?

The solution to 3x^2-13y+12=0 is Parabola with (h,k)=(0, 12/13),p= 13/12

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3x^2-13y+12=0

3 x^{2} - 13 y + 12 = 0

(h, k) = (0, \frac{12}{13}), p = \frac{13}{12}

Solution steps

3 x^{2} - 13 y + 12 = 0

Rewrite

3 x^{2} - 13 y + 12 = 0

in the standard form:

4 \cdot \frac{13}{12} (y - \frac{12}{13}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{12}{13}), p = \frac{13}{12}

(x - 2)^{2} = 4 y

(5 x - 4) = \frac{y}{5 x - 4}

(y - 2)^{2} = 4 (x + 2)

x^{2} = - 4 (y - 1)

(y + 4)^{2} = - 16 (x + 2)

What is 3x^2-13y+12=0 ?
The solution to 3x^2-13y+12=0 is Parabola with (h,k)=(0, 12/13),p= 13/12