What is y^2-24x+6y-105=0 ?

The solution to y^2-24x+6y-105=0 is Parabola with (h,k)=(-19/4 ,-3),p=6

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y^2-24x+6y-105=0

y^{2} - 24 x + 6 y - 105 = 0

(h, k) = (- \frac{19}{4}, - 3), p = 6

Solution steps

y^{2} - 24 x + 6 y - 105 = 0

Rewrite

y^{2} - 24 x + 6 y - 105 = 0

in the standard form

4 \cdot 6 (x - (- \frac{19}{4})) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{19}{4}, - 3), p = 6

(x - 1)^{2} = - 48 (y - 1)

3 x^{2} - 2 y = 0

y^{2} = 8 (x + 3)

y \geq - 4 x^{2} - 12 x - 8

x^{2} + 10 x - 2 y + 21 = 0

What is y^2-24x+6y-105=0 ?
The solution to y^2-24x+6y-105=0 is Parabola with (h,k)=(-19/4 ,-3),p=6