What is c=6000+3q^2-9q ?

The solution to c=6000+3q^2-9q is Parabola with (h,k)=(23973/4 , 3/2),p= 1/12

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c=6000+3q^2-9q

c = 6000 + 3 q^{2} - 9 q

(h, k) = (\frac{23973}{4}, \frac{3}{2}), p = \frac{1}{12}

Solution steps

c = 6000 + 3 q^{2} - 9 q

Rewrite

c = 6000 + 3 q^{2} - 9 q

in the standard form

4 \cdot \frac{1}{12} (c - \frac{23973}{4}) = (q - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{23973}{4}, \frac{3}{2}), p = \frac{1}{12}

f (x) (x)^{- 1} = 2 x + 1

y^{2} = 3 x - 5

3 y^{2} - 8 x + 5 y - 13 = 0

y^{(2)} = \frac{( 18 - 3 x )}{( 2 )}

\frac{1}{3} π r^{2} h = v

What is c=6000+3q^2-9q ?
The solution to c=6000+3q^2-9q is Parabola with (h,k)=(23973/4 , 3/2),p= 1/12