What is 5x^2-4x+P(x)=0 ?

The solution to 5x^2-4x+P(x)=0 is Parabola with (h,k)=(2/5 , 4/5),p=-1/20

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5x^2-4x+P(x)=0

5 x^{2} - 4 x + P (x) = 0

(h, k) = (\frac{2}{5}, \frac{4}{5}), p = - \frac{1}{20}

Solution steps

5 x^{2} - 4 x + y = 0

Rewrite

5 x^{2} - 4 x + y = 0

in the standard form

4 (- \frac{1}{20}) (y - \frac{4}{5}) = (x - \frac{2}{5})^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{5}, \frac{4}{5}), p = - \frac{1}{20}

x = 2 y^{2} + 2 y + 2

11 f (x) = 3 x^{2} + 5 x - 2

11 x^{2} + 7 y = 5

\frac{p ( x ) + x ^{2}}{n} = m

y 0.05 y + 0.01 x \leq 1.2

What is 5x^2-4x+P(x)=0 ?
The solution to 5x^2-4x+P(x)=0 is Parabola with (h,k)=(2/5 , 4/5),p=-1/20