What is 7x^2-28x-25y+3=0 ?

The solution to 7x^2-28x-25y+3=0 is Parabola with (h,k)=(2,-1),p= 25/28

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7x^2-28x-25y+3=0

7 x^{2} - 28 x - 25 y + 3 = 0

(h, k) = (2, - 1), p = \frac{25}{28}

Solution steps

7 x^{2} - 28 x - 25 y + 3 = 0

Rewrite

7 x^{2} - 28 x - 25 y + 3 = 0

in the standard form

4 \cdot \frac{25}{28} (y - (- 1)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 1), p = \frac{25}{28}

y + 1 = (x - 2)^{2}

36 (x - 5) - 64 (y - 2)^{2} = \frac{576}{25} 2304

v^{2} - v 0^{2} = 2 a (s - s^{0})

x^{2} + 76 x + 100 y + 100 = 0

4 x^{2} - y + 2 = 0

What is 7x^2-28x-25y+3=0 ?
The solution to 7x^2-28x-25y+3=0 is Parabola with (h,k)=(2,-1),p= 25/28