What is y^2-y-7x-54=0 ?

The solution to y^2-y-7x-54=0 is Parabola with (h,k)=(-31/4 , 1/2),p= 7/4

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y^2-y-7x-54=0

y^{2} - y - 7 x - 54 = 0

(h, k) = (- \frac{31}{4}, \frac{1}{2}), p = \frac{7}{4}

Solution steps

y^{2} - y - 7 x - 54 = 0

Rewrite

y^{2} - y - 7 x - 54 = 0

in the standard form

4 \cdot \frac{7}{4} (x - (- \frac{31}{4})) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{31}{4}, \frac{1}{2}), p = \frac{7}{4}

2 y^{2} - 49 x = 0

x^{2} = 15 y

- f (x) = x^{2} + 2 x - 8

x^{2} + (3 - i) z + 2 - 6 i = 0

y - 1 = 2 (x - 3)^{2}

What is y^2-y-7x-54=0 ?
The solution to y^2-y-7x-54=0 is Parabola with (h,k)=(-31/4 , 1/2),p= 7/4