What is (y-5)^2=-12(x-1/3) ?

The solution to (y-5)^2=-12(x-1/3) is Parabola with (h,k)=(1/3 ,5),p=-3

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(y-5)^2=-12(x-1/3)

(y - 5)^{2} = - 12 (x - \frac{1}{3})

(h, k) = (\frac{1}{3}, 5), p = - 3

Solution steps

(y - 5)^{2} = - 12 (x - \frac{1}{3})

Rewrite

(y - 5)^{2} = - 12 (x - \frac{1}{3})

in the standard form:

4 (- 3) (x - \frac{1}{3}) = (y - 5)^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{3}, 5), p = - 3

X^{2} = - 12 Y

(y + 5)^{2} = - 8 (x + 4)

y^{2} = 4 x - 1

2 x + y^{2} - y = 1

x + y^{2} - 3 \geq 0

What is (y-5)^2=-12(x-1/3) ?
The solution to (y-5)^2=-12(x-1/3) is Parabola with (h,k)=(1/3 ,5),p=-3