What is 1=-x^2-3x-2+0.5y ?

The solution to 1=-x^2-3x-2+0.5y is Parabola with (h,k)=(-3/2 , 3/2),p= 1/8

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1=-x^2-3x-2+0.5y

1 = - x^{2} - 3 x - 2 + 0.5 y

(h, k) = (- \frac{3}{2}, \frac{3}{2}), p = \frac{1}{8}

Solution steps

1 = - x^{2} - 3 x - 2 + 0.5 y

Rewrite

1 = - x^{2} - 3 x - 2 + 0.5 y

in the standard form

4 \cdot \frac{1}{8} (y - \frac{3}{2}) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, \frac{3}{2}), p = \frac{1}{8}

y^{2} + 16 x - 4 y + 1 = 0

y = - 4 x (x + 7)

x = - 3 (y - 5)^{2} + 1

(y - 3)^{2} = - 12 (x - 4)

x^{2} - 6 x + k (x) = 0

What is 1=-x^2-3x-2+0.5y ?
The solution to 1=-x^2-3x-2+0.5y is Parabola with (h,k)=(-3/2 , 3/2),p= 1/8