What is (y+6)^2= 1/2 (x-2) ?

The solution to (y+6)^2= 1/2 (x-2) is Parabola with (h,k)=(2,-6),p= 1/8

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(y+6)^2= 1/2 (x-2)

(y + 6)^{2} = \frac{1}{2} (x - 2)

(h, k) = (2, - 6), p = \frac{1}{8}

Solution steps

(y + 6)^{2} = \frac{1}{2} (x - 2)

Rewrite

(y + 6)^{2} = \frac{1}{2} (x - 2)

in the standard form:

4 \cdot \frac{1}{8} (x - 2) = (y - (- 6))^{2}

Therefore parabola properties are:

(h, k) = (2, - 6), p = \frac{1}{8}

\frac{x ^{2}}{4} = 4 + z

x^{2} + 8 x - 8 y = 16

y = - x^{2} - 5 x - 2

y \frac{1}{2 ( x + 1 )} = \frac{1}{5 ( y + 1 )}

x = (y - 2)^{2} - 1

What is (y+6)^2= 1/2 (x-2) ?
The solution to (y+6)^2= 1/2 (x-2) is Parabola with (h,k)=(2,-6),p= 1/8