What is f(x)(x)^{-1}=x+3 ?

The solution to f(x)(x)^{-1}=x+3 is Parabola with (h,k)=(-3/2 ,-9/4),p= 1/4

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f(x)(x)^{-1}=x+3

f (x) (x)^{- 1} = x + 3

(h, k) = (- \frac{3}{2}, - \frac{9}{4}), p = \frac{1}{4}

Solution steps

y x^{- 1} = x + 3

Rewrite

y x^{- 1} - x - 3 = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{9}{4})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{9}{4}), p = \frac{1}{4}

x^{2} + 2 z - 15 = 0

2 x^{2} + 92 = - 4 r (x)

25 y^{2} - x = 0

3 x^{2} + 2 x - 7 = O

(y + 3)^{2} = 2 (x - 4)

What is f(x)(x)^{-1}=x+3 ?
The solution to f(x)(x)^{-1}=x+3 is Parabola with (h,k)=(-3/2 ,-9/4),p= 1/4