What is -x^2-9x+y-14<0 ?

The solution to -x^2-9x+y-14<0 is Parabola with (h,k)=(-9/2 ,-25/4),p= 1/4

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-x^2-9x+y-14<0

- x^{2} - 9 x + y - 14 < 0

(h, k) = (- \frac{9}{2}, - \frac{25}{4}), p = \frac{1}{4}

Solution steps

- x^{2} - 9 x + y - 14 < 0

Rewrite

- x^{2} - 9 x + y - 14 < 0

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{25}{4})) = (x - (- \frac{9}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{9}{2}, - \frac{25}{4}), p = \frac{1}{4}

1 f (x) = - 5 x^{2} + 8

(x + 3)^{2} = - y

9 x - 5 y^{2} = 2

x^{2} - 2 x = 8 y + 17

f (x) = - \frac{3}{2} (x + 8) (x + 4)

What is -x^2-9x+y-14<0 ?
The solution to -x^2-9x+y-14<0 is Parabola with (h,k)=(-9/2 ,-25/4),p= 1/4