What is (y-8)^2=-2*(-8)(x+4) ?

The solution to (y-8)^2=-2*(-8)(x+4) is Parabola with (h,k)=(-4,8),p=4

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(y-8)^2=-2*(-8)(x+4)

(y - 8)^{2} = - 2 \cdot (- 8) (x + 4)

(h, k) = (- 4, 8), p = 4

Solution steps

(y - 8)^{2} = - 2 (- 8) (x + 4)

Rewrite

(y - 8)^{2} = - 2 (- 8) (x + 4)

in the standard form:

4 \cdot 4 (x - (- 4)) = (y - 8)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 8), p = 4

y^{2} + 12 x - 4 y + 1 = 0

y^{2} = - 4 (X - 1)

x^{2} - 4 y + 6 x - 7 = 0

\frac{v}{s} = \frac{v}{s + 1} + 1

56 y = 12 x^{2}

What is (y-8)^2=-2*(-8)(x+4) ?
The solution to (y-8)^2=-2*(-8)(x+4) is Parabola with (h,k)=(-4,8),p=4