What is (y+2)^2= 5/4 (x-4) ?

The solution to (y+2)^2= 5/4 (x-4) is Parabola with (h,k)=(4,-2),p= 5/16

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(y+2)^2= 5/4 (x-4)

(y + 2)^{2} = \frac{5}{4} (x - 4)

(h, k) = (4, - 2), p = \frac{5}{16}

Solution steps

(y + 2)^{2} = \frac{5}{4} (x - 4)

Rewrite

(y + 2)^{2} = \frac{5}{4} (x - 4)

in the standard form:

4 \cdot \frac{5}{16} (x - 4) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (4, - 2), p = \frac{5}{16}

\frac{3 y}{y - 4} = \frac{x}{( y - 4 ) ( y - 3 )}

x = - 2 (y + 6)^{2}

y^{2} + x = 5

y - 2 x - x^{2} = 2

y^{2} - 12 y + 8 x = 0

What is (y+2)^2= 5/4 (x-4) ?
The solution to (y+2)^2= 5/4 (x-4) is Parabola with (h,k)=(4,-2),p= 5/16