What is 2x^2+5+2=-3(2y+1) ?

The solution to 2x^2+5+2=-3(2y+1) is Parabola with (h,k)=(0,-5/3),p=-3/4

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2x^2+5+2=-3(2y+1)

2 x^{2} + 5 + 2 = - 3 (2 y + 1)

(h, k) = (0, - \frac{5}{3}), p = - \frac{3}{4}

Solution steps

2 x^{2} + 5 + 2 = - 3 (2 y + 1)

Rewrite

2 x^{2} + 5 + 2 = - 3 (2 y + 1)

in the standard form:

4 (- \frac{3}{4}) (y - (- \frac{5}{3})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{5}{3}), p = - \frac{3}{4}

x^{2} + 2 x + 12 y = - 37

(y + 3)^{2} - x = 36

x^{2} - 8 y + 2 x + 10 = 0

x + 2 y^{2} = 32

x = (y + 4)^{2} + 5

What is 2x^2+5+2=-3(2y+1) ?
The solution to 2x^2+5+2=-3(2y+1) is Parabola with (h,k)=(0,-5/3),p=-3/4