What is 4x^2-20k(x)+16=0 ?

The solution to 4x^2-20k(x)+16=0 is Parabola with (h,k)=(0, 4/5),p= 5/4

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4x^2-20k(x)+16=0

4 x^{2} - 20 k (x) + 16 = 0

(h, k) = (0, \frac{4}{5}), p = \frac{5}{4}

Solution steps

4 x^{2} - 20 y + 16 = 0

Rewrite

4 x^{2} - 20 y + 16 = 0

in the standard form:

4 \cdot \frac{5}{4} (y - \frac{4}{5}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{4}{5}), p = \frac{5}{4}

y > - x^{2} + 7

(x + 5)^{2} = 12 (y - 2)

y > - x^{2} + 5

2 x^{2} + 7 y + 3 = 0

y > - x^{2} + 4

What is 4x^2-20k(x)+16=0 ?
The solution to 4x^2-20k(x)+16=0 is Parabola with (h,k)=(0, 4/5),p= 5/4