What is (y-3)=-1/4 (x+4)^2 ?

The solution to (y-3)=-1/4 (x+4)^2 is Parabola with (h,k)=(-4,3),p=-1

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(y-3)=-1/4 (x+4)^2

(y - 3) = - \frac{1}{4} (x + 4)^{2}

(h, k) = (- 4, 3), p = - 1

Solution steps

(y - 3) = - \frac{1}{4} (x + 4)^{2}

Rewrite

(y - 3) = - \frac{1}{4} (x + 4)^{2}

in the standard form:

4 (- 1) (y - 3) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, 3), p = - 1

(x - 3)^{2} = 20 (y + 2)

x, 5 x - 6 - \frac{1}{2} k (x)^{2} + 2 k (x)^{2} = 0

a 9 a + 6 c = 8 a + 10 c

y > - x^{2} - 4 x + 2

w^{2} - w^{2} = - \frac{s}{m}

What is (y-3)=-1/4 (x+4)^2 ?
The solution to (y-3)=-1/4 (x+4)^2 is Parabola with (h,k)=(-4,3),p=-1