What is 5x^2-4y-10x-8y-19=0 ?

The solution to 5x^2-4y-10x-8y-19=0 is Parabola with (h,k)=(1,-2),p= 3/5

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5x^2-4y-10x-8y-19=0

5 x^{2} - 4 y - 10 x - 8 y - 19 = 0

(h, k) = (1, - 2), p = \frac{3}{5}

Solution steps

5 x^{2} - 4 y - 10 x - 8 y - 19 = 0

Rewrite

5 x^{2} - 4 y - 10 x - 8 y - 19 = 0

in the standard form

4 \cdot \frac{3}{5} (y - (- 2)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 2), p = \frac{3}{5}

\frac{7 y}{x + 1} = 3 \frac{7}{y + 1}

y^{2} = 6 - 2 x

8 (x - 5) = (y - 2)^{2}

3^{2} + 3 y^{2} - 6 x + 9 y - 14 = 0

2 f (x) = - 3 x^{2} + x - 1

What is 5x^2-4y-10x-8y-19=0 ?
The solution to 5x^2-4y-10x-8y-19=0 is Parabola with (h,k)=(1,-2),p= 3/5