What is g(x)(2*2-3)=x^2+1 ?

The solution to g(x)(2*2-3)=x^2+1 is Parabola with (h,k)=(0,1),p= 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

g(x)(2*2-3)=x^2+1

g (x) (2 \cdot 2 - 3) = x^{2} + 1

(h, k) = (0, 1), p = \frac{1}{4}

Solution steps

y (2 \cdot 2 - 3) = x^{2} + 1

Rewrite

y (2 \cdot 2 - 3) = x^{2} + 1

in the standard form:

4 \cdot \frac{1}{4} (y - 1) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 1), p = \frac{1}{4}

A 4 n A 3 n + 1 - C n - 4 n = \frac{24}{23}

x^{2} + 2 - 2 y = 0

(x - 7)^{2} = - 6 (y - 4)

x, S (x)^{1} = x (40 - 2 x)

6 y = (x + 2)^{2} - 2

What is g(x)(2*2-3)=x^2+1 ?
The solution to g(x)(2*2-3)=x^2+1 is Parabola with (h,k)=(0,1),p= 1/4