What is 4x^2+7x+k(x)=0 ?

The solution to 4x^2+7x+k(x)=0 is Parabola with (h,k)=(-7/8 , 49/16),p=-1/16

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4x^2+7x+k(x)=0

4 x^{2} + 7 x + k (x) = 0

(h, k) = (- \frac{7}{8}, \frac{49}{16}), p = - \frac{1}{16}

Solution steps

4 x^{2} + 7 x + y = 0

Rewrite

4 x^{2} + 7 x + y = 0

in the standard form

4 (- \frac{1}{16}) (y - \frac{49}{16}) = (x - (- \frac{7}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{8}, \frac{49}{16}), p = - \frac{1}{16}

y^{2} - 3 x + 1 = 5 x

- x^{2} - 5 y + 6 \geq 0

4 x^{2} - y = 3

4 x^{2} - y = 1

y^{2} - 14 y - 4 x + 33 = 0

What is 4x^2+7x+k(x)=0 ?
The solution to 4x^2+7x+k(x)=0 is Parabola with (h,k)=(-7/8 , 49/16),p=-1/16