What is (y)^2-12x-10(y)+13=0 ?

The solution to (y)^2-12x-10(y)+13=0 is Parabola with (h,k)=(-1,5),p=3

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(y)^2-12x-10(y)+13=0

(y)^{2} - 12 x - 10 (y) + 13 = 0

(h, k) = (- 1, 5), p = 3

Solution steps

y^{2} - 12 x - 10 y + 13 = 0

Rewrite

y^{2} - 12 x - 10 y + 13 = 0

in the standard form

4 \cdot 3 (x - (- 1)) = (y - 5)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 5), p = 3

4 x^{2} + 16 y + 40 x + 64 y + 100 = 0

x^{2} + 8 x + 3 - k (x) = 0

2 a^{2} + 3 a + b = - 2

(y + 1)^{2} = 4 x

16 x^{2} + 56 x + 144 y + 517 = 0

What is (y)^2-12x-10(y)+13=0 ?
The solution to (y)^2-12x-10(y)+13=0 is Parabola with (h,k)=(-1,5),p=3