What is yy+3= 4/3 (x+2) ?

The solution to yy+3= 4/3 (x+2) is Parabola with (h,k)=(1/4 ,0),p= 1/3

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yy+3= 4/3 (x+2)

yy + 3 = \frac{4}{3} (x + 2)

(h, k) = (\frac{1}{4}, 0), p = \frac{1}{3}

Solution steps

yy + 3 = \frac{4}{3} (x + 2)

Rewrite

yy + 3 = \frac{4}{3} (x + 2)

in the standard form:

4 \cdot \frac{1}{3} (x - \frac{1}{4}) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{4}, 0), p = \frac{1}{3}

(f (x) + 4) = x^{2}

\frac{( x + 5 ) ^{2}}{25} - \frac{( y + 1 ^{2} )}{36} = 1

(y - 3)^{2} - x = 16

(1 - x)^{2} = x^{2} + y^{2}

4 x^{2} - 3 y - 8 x + 6 y + 1 = 0

What is yy+3= 4/3 (x+2) ?
The solution to yy+3= 4/3 (x+2) is Parabola with (h,k)=(1/4 ,0),p= 1/3