What is (x+3)^2+(y-2)=13 ?

The solution to (x+3)^2+(y-2)=13 is Parabola with (h,k)=(-3,15),p=-1/4

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(x+3)^2+(y-2)=13

(x + 3)^{2} + (y - 2) = 13

(h, k) = (- 3, 15), p = - \frac{1}{4}

Solution steps

(x + 3)^{2} + (y - 2) = 13

Rewrite

(x + 3)^{2} + (y - 2) = 13

in the standard form:

4 (- \frac{1}{4}) (y - 15) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 15), p = - \frac{1}{4}

y = - x^{2} + 22 x - 105

x = \frac{1}{20} y^{2}

x^{2} - 43 y + 348 = 0

6 x^{2} - 60 x + y + 145 = 0

y = x^{2} - 12 x + 11

What is (x+3)^2+(y-2)=13 ?
The solution to (x+3)^2+(y-2)=13 is Parabola with (h,k)=(-3,15),p=-1/4