What is (x-2)^2=-33(y-4) ?

The solution to (x-2)^2=-33(y-4) is Parabola with (h,k)=(2,4),p=-33/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2=-33(y-4)

(x - 2)^{2} = - 33 (y - 4)

(h, k) = (2, 4), p = - \frac{33}{4}

Solution steps

(x - 2)^{2} = - 33 (y - 4)

Rewrite

(x - 2)^{2} = - 33 (y - 4)

in the standard form:

4 (- \frac{33}{4}) (y - 4) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 4), p = - \frac{33}{4}

y^{2} - 6 y + 9 + 4 x - 20 = 0

y = 4 x^{2} - x - 6

4 y^{2} + 16 x = 0

y^{2} + 8 y - 2 x + 22 = 0

9^{2} + 4 y^{2} - 54 x + 8 y + 113 = 0

What is (x-2)^2=-33(y-4) ?
The solution to (x-2)^2=-33(y-4) is Parabola with (h,k)=(2,4),p=-33/4