What is f(x)-4=x^{(2)}-2x+5 ?

The solution to f(x)-4=x^{(2)}-2x+5 is Parabola with (h,k)=(1,8),p= 1/4

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f(x)-4=x^{(2)}-2x+5

f (x) - 4 = x^{(2)} - 2 x + 5

(h, k) = (1, 8), p = \frac{1}{4}

Solution steps

y - 4 = x^{2} - 2 x + 5

Rewrite

y - 4 = x^{2} - 2 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - 8) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 8), p = \frac{1}{4}

(x + 7)^{2} = x^{2} + (y - 5)^{2}

2 \cdot \frac{x}{x - 3} + 2 (x - 3) = 28

y^{2} + 4 x - 9 = 0

\frac{( x - 5 )}{3} = \frac{3 x - 1}{5} + 2 E (x, y) y

(y + 3)^{2} = x

What is f(x)-4=x^{(2)}-2x+5 ?
The solution to f(x)-4=x^{(2)}-2x+5 is Parabola with (h,k)=(1,8),p= 1/4