What is (x-0)+(y-8)^2=25 ?

The solution to (x-0)+(y-8)^2=25 is Parabola with (h,k)=(25,8),p=-1/4

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(x-0)+(y-8)^2=25

(x - 0) + (y - 8)^{2} = 25

(h, k) = (25, 8), p = - \frac{1}{4}

Solution steps

x - 0 + (y - 8)^{2} = 25

Rewrite

x - 0 + (y - 8)^{2} = 25

in the standard form:

4 (- \frac{1}{4}) (x - 25) = (y - 8)^{2}

Therefore parabola properties are:

(h, k) = (25, 8), p = - \frac{1}{4}

y - 1 = - \frac{1}{3} x (x - 4)

(x - 4)^{2} = 12 (y + 1)

2 x^{2} - y + 7 = 0

20 x - 4 y = - 4 x^{2}

2 x^{2} - 7 y = 0

What is (x-0)+(y-8)^2=25 ?
The solution to (x-0)+(y-8)^2=25 is Parabola with (h,k)=(25,8),p=-1/4