What is x-3y^2+3y=-18 ?

The solution to x-3y^2+3y=-18 is Parabola with (h,k)=(-75/4 , 1/2),p= 1/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x-3y^2+3y=-18

x - 3 y^{2} + 3 y = - 18

(h, k) = (- \frac{75}{4}, \frac{1}{2}), p = \frac{1}{12}

Solution steps

x - 3 y^{2} + 3 y = - 18

Rewrite

x - 3 y^{2} + 3 y = - 18

in the standard form

4 \cdot \frac{1}{12} (x - (- \frac{75}{4})) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{75}{4}, \frac{1}{2}), p = \frac{1}{12}

4 x + y^{2} + 8 = 0

y \leq x^{2} - 6 x + 11

f, f (x)^{2} = 3 x + \frac{5}{3}

- y = 2 x^{2} + 2 x + 2

y + 16 x = x^{2} + 8

What is x-3y^2+3y=-18 ?
The solution to x-3y^2+3y=-18 is Parabola with (h,k)=(-75/4 , 1/2),p= 1/12