What is x= 1/12 (y+3)^2-1 ?

The solution to x= 1/12 (y+3)^2-1 is Parabola with (h,k)=(-1,-3),p=3

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x= 1/12 (y+3)^2-1

x = \frac{1}{12} (y + 3)^{2} - 1

(h, k) = (- 1, - 3), p = 3

Solution steps

x = \frac{1}{12} (y + 3)^{2} - 1

Rewrite

x = \frac{1}{12} (y + 3)^{2} - 1

in the standard form:

4 \cdot 3 (x - (- 1)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 3), p = 3

3 x^{2} - 5 y = 2 x

(x - 2)^{2} + (y - 1) = 8

x^{2} - x - y = 1

(x + 9) 2 + y^{2} = 100

x + y^{2} = a

What is x= 1/12 (y+3)^2-1 ?
The solution to x= 1/12 (y+3)^2-1 is Parabola with (h,k)=(-1,-3),p=3