What is (x+3)2+(y+1)^2=36 ?

The solution to (x+3)2+(y+1)^2=36 is Parabola with (h,k)=(15,-1),p=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+3)2+(y+1)^2=36

(x + 3) 2 + (y + 1)^{2} = 36

(h, k) = (15, - 1), p = - \frac{1}{2}

Solution steps

(x + 3) \cdot 2 + (y + 1)^{2} = 36

Rewrite

(x + 3) \cdot 2 + (y + 1)^{2} = 36

in the standard form:

4 (- \frac{1}{2}) (x - 15) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (15, - 1), p = - \frac{1}{2}

x = 4 y^{2} - 4

x = y^{2} + 6 y - 4

x = y^{2} + 6 y - 7

x, 4 x^{2} + 3 w + 5 = 0

x^{2} - 4 x - 20 y + 184 = 0

What is (x+3)2+(y+1)^2=36 ?
The solution to (x+3)2+(y+1)^2=36 is Parabola with (h,k)=(15,-1),p=-1/2