What is (x-4)^2-2(y+8)=0 ?

The solution to (x-4)^2-2(y+8)=0 is Parabola with (h,k)=(4,-8),p= 1/2

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(x-4)^2-2(y+8)=0

(x - 4)^{2} - 2 (y + 8) = 0

(h, k) = (4, - 8), p = \frac{1}{2}

Solution steps

(x - 4)^{2} - 2 (y + 8) = 0

Rewrite

(x - 4)^{2} - 2 (y + 8) = 0

in the standard form:

4 \cdot \frac{1}{2} (y - (- 8)) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, - 8), p = \frac{1}{2}

- x^{2} - 11 x - y - 28 \geq 0

x = \frac{( 5 y + 3 )}{7 x - 13}

(x - h)^{(2)} = 4 p (y - k)

x = 2 - y - y^{2}

(x - 3)^{2} = 16 (y - 1)

What is (x-4)^2-2(y+8)=0 ?
The solution to (x-4)^2-2(y+8)=0 is Parabola with (h,k)=(4,-8),p= 1/2