What is -2y^{(2)}+4y-x-7=0 ?

The solution to -2y^{(2)}+4y-x-7=0 is Parabola with (h,k)=(-5,1),p=-1/8

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-2y^{(2)}+4y-x-7=0

- 2 y^{(2)} + 4 y - x - 7 = 0

(h, k) = (- 5, 1), p = - \frac{1}{8}

Solution steps

- 2 y^{2} + 4 y - x - 7 = 0

Rewrite

- 2 y^{2} + 4 y - x - 7 = 0

in the standard form

4 (- \frac{1}{8}) (x - (- 5)) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (- 5, 1), p = - \frac{1}{8}

x^{2} + y - 37 = 0

y = - 6 x^{2} + 1

x^{2} + 12 r (x) = - 32

y = - 6 x^{2} + 5

y^{(2)} = 9 - x

What is -2y^{(2)}+4y-x-7=0 ?
The solution to -2y^{(2)}+4y-x-7=0 is Parabola with (h,k)=(-5,1),p=-1/8