What is 0.2x^2-0.8x-0.2=o ?

The solution to 0.2x^2-0.8x-0.2=o is Parabola with (h,k)=(2,-1),p=1.25

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0.2x^2-0.8x-0.2=o

0.2 x^{2} - 0.8 x - 0.2 = o

(h, k) = (2, - 1), p = 1.25

Solution steps

0.2 x^{2} - 0.8 x - 0.2 = o

Rewrite

0.2 x^{2} - 0.8 x - 0.2 = o

in the standard form

4 \cdot 1.25 (o - (- 1)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 1), p = 1.25

q^{1} = 105 - 3 p^{1} + p^{2}

x^{2} = 50 y

- x^{2} + y - 2 = 0

(x - 3)^{2} + (y - 2)^{2} = (x + 3)^{2} - (y + 2)^{2}

9 y = x^{2}

What is 0.2x^2-0.8x-0.2=o ?
The solution to 0.2x^2-0.8x-0.2=o is Parabola with (h,k)=(2,-1),p=1.25