What is 3x^2+9x-5y-2=0 ?

The solution to 3x^2+9x-5y-2=0 is Parabola with (h,k)=(-3/2 ,-7/4),p= 5/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2+9x-5y-2=0

3 x^{2} + 9 x - 5 y - 2 = 0

(h, k) = (- \frac{3}{2}, - \frac{7}{4}), p = \frac{5}{12}

Solution steps

3 x^{2} + 9 x - 5 y - 2 = 0

Rewrite

3 x^{2} + 9 x - 5 y - 2 = 0

in the standard form

4 \cdot \frac{5}{12} (y - (- \frac{7}{4})) = (x - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{2}, - \frac{7}{4}), p = \frac{5}{12}

y = 20 x - 2 x^{2} + 10

(y + 3)^{2} = - 12 (x - 2)

x - y^{(2)} = 2

(x - 1)^{2} = 5 (y + 3)

y = x^{2} - 6 x - 10

What is 3x^2+9x-5y-2=0 ?
The solution to 3x^2+9x-5y-2=0 is Parabola with (h,k)=(-3/2 ,-7/4),p= 5/12