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Popular >

foci 2x^2+x-6

Solution

foci

2 x^{2} + x - 6

Solution

(- \frac{1}{4}, - 6)

Solution steps

Rewrite

y = 2 x^{2} + x - 6

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{49}{8})) = (x - (- \frac{1}{4}))^{2}

(h, k) = (- \frac{1}{4}, - \frac{49}{8}), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{1}{4}, - \frac{49}{8})

along the y-axis

(- \frac{1}{4}, - \frac{49}{8} + p)

= (- \frac{1}{4}, - \frac{49}{8} + \frac{1}{8})

Refine

(- \frac{1}{4}, - 6)

Graph

Popular Examples

foci y=2x^2-6x+10 foci

y = 2 x^{2} - 6 x + 10

foci y=x^2-x-6 foci

y = x^{2} - x - 6

foci y=(x^2x^1)/x foci

y = \frac{x ^{2} x ^{1}}{x}

foci x= 1/20 y^2 foci

x = \frac{1}{20} y^{2}

foci y=-x^2-x-1 foci

y = - x^{2} - x - 1

Frequently Asked Questions (FAQ)

What is the foci 2x^2+x-6 ?
The foci 2x^2+x-6 is (-1/4 ,-6)