leitkurve x^2+17x+16

Lösung

leitkurve

x^{2} + 17 x + 16

y = - \frac{113}{2}

Schritte zur Lösung

Rewrite

y = x^{2} + 17 x + 16

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{225}{4})) = (x - (- \frac{17}{2}))^{2}

(h, k) = (- \frac{17}{2}, - \frac{225}{4}), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- \frac{17}{2}, - \frac{225}{4})

y-coordinate

y = - \frac{225}{4} - p

y = - \frac{225}{4} - \frac{1}{4}

Fasse zusammen

y = - \frac{113}{2}

d i rec t r i x y = (x + 1) (x + 2)

d i rec t r i x y = x^{2} + x + 1

d i rec t r i x y = x^{2} + x + 3

d i rec t r i x - 2 x = (y + 3)^{2} + 6

d i rec t r i x y = \frac{3 x ^{3} - 6 x ^{2}}{x - 2}