What is the general solution for 4cos(t)=0 ?

The general solution for 4cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4cos(t)=0

4 cos (t) = 0

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

Degrees

t = 9 0^{\circ} + 36 0^{\circ} n, t = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

4 cos (t) = 0

Divide both sides by

4

4 cos (t) = 0

Divide both sides by

4

\frac{4 cos ( t )}{4} = \frac{0}{4}

Simplify

cos (t) = 0

cos (t) = 0

General solutions for

cos (t) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

t = \frac{π}{2} + 2 πn, t = \frac{3 π}{2} + 2 πn

7 sec^{3} (x) + 16 sec^{2} (x) + 11 sec (x) + 2 = 0

1 + sin (5 x) = 0

0 = \frac{π}{2} - 2 arctan (\frac{\frac{π}{2} - 2 - c}{\frac{π}{2} - c})

9 arcsin (x) = 3 π

2 sin (2 x + 10) - 3 = 0

What is the general solution for 4cos(t)=0 ?
The general solution for 4cos(t)=0 is t= pi/2+2pin,t=(3pi)/2+2pin