What is the general solution for 3+6sin(3t)=0 ?

The general solution for 3+6sin(3t)=0 is t=(7pi}{18}+(2pin)/3 ,t=(11pi)/(18)+\frac{2pin)/3

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Popular >

3+6sin(3t)=0

Solution

3 + 6 sin (3 t) = 0

Solution

t = \frac{7 π}{18} + \frac{2 πn}{3}, t = \frac{11 π}{18} + \frac{2 πn}{3}

Degrees

t = 7 0^{\circ} + 12 0^{\circ} n, t = 11 0^{\circ} + 12 0^{\circ} n

Solution steps

3 + 6 sin (3 t) = 0

Move

3

to the right side

3 + 6 sin (3 t) = 0

Subtract

3

from both sides

3 + 6 sin (3 t) - 3 = 0 - 3

Simplify

6 sin (3 t) = - 3

6 sin (3 t) = - 3

Divide both sides by

6

6 sin (3 t) = - 3

Divide both sides by

6

\frac{6 sin ( 3 t )}{6} = \frac{- 3}{6}

Simplify

\frac{6 sin ( 3 t )}{6} = \frac{- 3}{6}

Simplify

\frac{6 sin ( 3 t )}{6} : sin (3 t)

\frac{6 sin ( 3 t )}{6}

Divide the numbers:

\frac{6}{6} = 1

= sin (3 t)

Simplify

\frac{- 3}{6} : - \frac{1}{2}

\frac{- 3}{6}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{6}

Cancel the common factor:

3

= - \frac{1}{2}

sin (3 t) = - \frac{1}{2}

sin (3 t) = - \frac{1}{2}

sin (3 t) = - \frac{1}{2}

General solutions for

sin (3 t) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

3 t = \frac{7 π}{6} + 2 πn, 3 t = \frac{11 π}{6} + 2 πn

3 t = \frac{7 π}{6} + 2 πn, 3 t = \frac{11 π}{6} + 2 πn

Solve

3 t = \frac{7 π}{6} + 2 πn : t = \frac{7 π}{18} + \frac{2 πn}{3}

3 t = \frac{7 π}{6} + 2 πn

Divide both sides by

3

3 t = \frac{7 π}{6} + 2 πn

Divide both sides by

3

\frac{3 t}{3} = \frac{\frac{7 π}{6}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 t}{3} = \frac{\frac{7 π}{6}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 t}{3} : t

\frac{3 t}{3}

Divide the numbers:

\frac{3}{3} = 1

= t

Simplify

\frac{\frac{7 π}{6}}{3} + \frac{2 πn}{3} : \frac{7 π}{18} + \frac{2 πn}{3}

\frac{\frac{7 π}{6}}{3} + \frac{2 πn}{3}

\frac{\frac{7 π}{6}}{3} = \frac{7 π}{18}

\frac{\frac{7 π}{6}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{7 π}{6 \cdot 3}

Multiply the numbers:

6 \cdot 3 = 18

= \frac{7 π}{18}

= \frac{7 π}{18} + \frac{2 πn}{3}

t = \frac{7 π}{18} + \frac{2 πn}{3}

t = \frac{7 π}{18} + \frac{2 πn}{3}

t = \frac{7 π}{18} + \frac{2 πn}{3}

Solve

3 t = \frac{11 π}{6} + 2 πn : t = \frac{11 π}{18} + \frac{2 πn}{3}

3 t = \frac{11 π}{6} + 2 πn

Divide both sides by

3

3 t = \frac{11 π}{6} + 2 πn

Divide both sides by

3

\frac{3 t}{3} = \frac{\frac{11 π}{6}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 t}{3} = \frac{\frac{11 π}{6}}{3} + \frac{2 πn}{3}

Simplify

\frac{3 t}{3} : t

\frac{3 t}{3}

Divide the numbers:

\frac{3}{3} = 1

= t

Simplify

\frac{\frac{11 π}{6}}{3} + \frac{2 πn}{3} : \frac{11 π}{18} + \frac{2 πn}{3}

\frac{\frac{11 π}{6}}{3} + \frac{2 πn}{3}

\frac{\frac{11 π}{6}}{3} = \frac{11 π}{18}

\frac{\frac{11 π}{6}}{3}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{11 π}{6 \cdot 3}

Multiply the numbers:

6 \cdot 3 = 18

= \frac{11 π}{18}

= \frac{11 π}{18} + \frac{2 πn}{3}

t = \frac{11 π}{18} + \frac{2 πn}{3}

t = \frac{11 π}{18} + \frac{2 πn}{3}

t = \frac{11 π}{18} + \frac{2 πn}{3}

t = \frac{7 π}{18} + \frac{2 πn}{3}, t = \frac{11 π}{18} + \frac{2 πn}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for 3+6sin(3t)=0 ?
The general solution for 3+6sin(3t)=0 is t=(7pi}{18}+(2pin)/3 ,t=(11pi)/(18)+\frac{2pin)/3