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受欢迎的三角函数 >

6cos^2(pi/8)-3

解答

6 cos^{2} (\frac{π}{8}) - 3

解答

\frac{3 2}{2}

+1

十进制

2.12132 \dots

求解步骤

6 cos^{2} (\frac{π}{8}) - 3

使用三角恒等式改写:

cos^{2} (\frac{π}{8}) = \frac{1 + cos ( \frac{π}{4} )}{2}

cos^{2} (\frac{π}{8})

利用以下特性:

cos^{2} (θ) = \frac{1 + cos ( 2 θ )}{2}

使用倍角公式

cos (2 θ) = 2 cos^{2} (θ) - 1

交换两边

2 cos^{2} (θ) - 1 = cos (2 θ)

两边加上

1

2 sin^{2} (θ) = 1 + cos (2 θ)

两边除以

2

cos^{2} (θ) = \frac{1 + cos ( 2 θ )}{2}

= \frac{1 + cos ( 2 \cdot \frac{π}{8} )}{2}

化简:

2 \cdot \frac{π}{8} = \frac{π}{4}

2 \cdot \frac{π}{8}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{8}

约分:

2

= \frac{π}{4}

= \frac{1 + cos ( \frac{π}{4} )}{2}

= 6 \cdot \frac{1 + cos ( \frac{π}{4} )}{2} - 3

6 \cdot \frac{1 + cos ( \frac{π}{4} )}{2} - 3 = 3 cos (\frac{π}{4})

6 \cdot \frac{1 + cos ( \frac{π}{4} )}{2} - 3

6 \cdot \frac{1 + cos ( \frac{π}{4} )}{2} = 3 (cos (\frac{π}{4}) + 1)

6 \cdot \frac{1 + cos ( \frac{π}{4} )}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 1 + cos ( \frac{π}{4} ) ) \cdot 6}{2}

数字相除:

\frac{6}{2} = 3

= 3 (cos (\frac{π}{4}) + 1)

= 3 (cos (\frac{π}{4}) + 1) - 3

乘开

3 (cos (\frac{π}{4}) + 1) : 3 cos (\frac{π}{4}) + 3

3 (cos (\frac{π}{4}) + 1)

使用分配律:

a (b + c) = ab + a c

a = 3, b = cos (\frac{π}{4}), c = 1

= 3 cos (\frac{π}{4}) + 3 \cdot 1

数字相乘:

3 \cdot 1 = 3

= 3 cos (\frac{π}{4}) + 3

= 3 cos (\frac{π}{4}) + 3 - 3

3 - 3 = 0

= 3 cos (\frac{π}{4})

= 3 cos (\frac{π}{4})

使用以下普通恒等式:

cos (\frac{π}{4}) = \frac{2}{2}

cos (\frac{π}{4})

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

= 3 \cdot \frac{2}{2}

化简

3 \cdot \frac{2}{2} : \frac{3 2}{2}

3 \cdot \frac{2}{2}

分式相乘:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 3}{2}

使用根式运算法则:

n a = a^{\frac{1}{n}}

2 = 2^{\frac{1}{2}}

= \frac{3 \cdot 2 ^{\frac{1}{2}}}{2}

使用指数法则:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{2}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{2}}}

= \frac{3}{2 ^{1 - \frac{1}{2}}}

数字相减:

1 - \frac{1}{2} = \frac{1}{2}

= \frac{3}{2 ^{\frac{1}{2}}}

使用根式运算法则:

a^{\frac{1}{n}} = n a

2^{\frac{1}{2}} = 2

= \frac{3}{2}

\frac{3}{2}

有理化:

\frac{3 2}{2}

\frac{3}{2}

乘以共轭根式

\frac{2}{2}

= \frac{3 2}{2 2}

22 = 2

22

使用根式运算法则:

a a = a

22 = 2

= 2

= \frac{3 2}{2}

= \frac{3 2}{2}

= \frac{3 2}{2}

流行的例子

csc (5 9^{\circ})

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