What is the general solution for tan(-y)=0.9 ?

The general solution for tan(-y)=0.9 is y=-0.73281…-pin

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tan(-y)=0.9

tan (- y) = 0.9

y = - 0.73281 \dots - πn

Degrees

y = - 41.98721 \dots^{\circ} - 18 0^{\circ} n

Solution steps

tan (- y) = 0.9

Apply trig inverse properties

tan (- y) = 0.9

General solutions for

tan (- y) = 0.9

tan (x) = a \Rightarrow x = arctan (a) + πn

- y = arctan (0.9) + πn

- y = arctan (0.9) + πn

Solve

- y = arctan (0.9) + πn : y = - arctan (0.9) - πn

- y = arctan (0.9) + πn

Divide both sides by

- 1

- y = arctan (0.9) + πn

Divide both sides by

- 1

\frac{- y}{- 1} = \frac{arctan ( 0.9 )}{- 1} + \frac{πn}{- 1}

Simplify

\frac{- y}{- 1} = \frac{arctan ( 0.9 )}{- 1} + \frac{πn}{- 1}

Simplify

\frac{- y}{- 1} : y

\frac{- y}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{y}{1}

Apply rule

\frac{a}{1} = a

= y

Simplify

\frac{arctan ( 0.9 )}{- 1} + \frac{πn}{- 1} : - arctan (0.9) - πn

\frac{arctan ( 0.9 )}{- 1} + \frac{πn}{- 1}

\frac{arctan ( 0.9 )}{- 1} = - arctan (0.9)

\frac{arctan ( 0.9 )}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{arctan ( 0.9 )}{1}

Apply rule

\frac{a}{1} = a

= - arctan (0.9)

= - arctan (0.9) + \frac{πn}{- 1}

\frac{πn}{- 1} = - πn

\frac{πn}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{πn}{1}

Apply rule

\frac{a}{1} = a

= - πn

= - arctan (0.9) - πn

y = - arctan (0.9) - πn

y = - arctan (0.9) - πn

y = - arctan (0.9) - πn

y = - arctan (0.9) - πn

Show solutions in decimal form

y = - 0.73281 \dots - πn

cos (θ) = 3 sin (θ)

arctan (x + 1 x - 1) + arctan (x - 12) = arctan (2)

sin (α) = \frac{1}{4}

3 cos^{2} (3 x) - \frac{9}{4} = 0

4 sin (θ) - 1 = 0

What is the general solution for tan(-y)=0.9 ?
The general solution for tan(-y)=0.9 is y=-0.73281…-pin