What is the general solution for sin(2x)=2sqrt(3)sin^2(x) ?

The general solution for sin(2x)=2sqrt(3)sin^2(x) is x=2pin,x=pi+2pin,x= pi/6+pin

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Popular >

sin(2x)=2sqrt(3)sin^2(x)

Solution

sin (2 x) = 23 sin^{2} (x)

Solution

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 3 0^{\circ} + 18 0^{\circ} n

Solution steps

sin (2 x) = 23 sin^{2} (x)

Subtract

23 sin^{2} (x)

from both sides

sin (2 x) - 23 sin^{2} (x) = 0

Rewrite using trig identities

sin (2 x) - 2 sin^{2} (x) 3

Use the Double Angle identity:

sin (2 x) = 2 sin (x) cos (x)

= 2 sin (x) cos (x) - 2 sin^{2} (x) 3

2 cos (x) sin (x) - 2 sin^{2} (x) 3 = 0

Factor

2 cos (x) sin (x) - 2 sin^{2} (x) 3 : 2 sin (x) (cos (x) - 3 sin (x))

2 cos (x) sin (x) - 2 sin^{2} (x) 3

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

sin^{2} (x) = sin (x) sin (x)

= 2 cos (x) sin (x) - 2 sin (x) sin (x) 3

Rewrite as

= 2 sin (x) cos (x) - 2 sin (x) sin (x) 3

Factor out common term

2 sin (x)

= 2 sin (x) (cos (x) - sin (x) 3)

2 sin (x) (cos (x) - 3 sin (x)) = 0

Solving each part separately

sin (x) = 0 or cos (x) - 3 sin (x) = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

cos (x) - 3 sin (x) = 0 : x = \frac{π}{6} + πn

cos (x) - 3 sin (x) = 0

Rewrite using trig identities

cos (x) - 3 sin (x) = 0

Divide both sides by

cos (x), cos (x) \neq = 0

\frac{cos ( x ) - 3 sin ( x )}{cos ( x )} = \frac{0}{cos ( x )}

Simplify

1 - \frac{3 sin ( x )}{cos ( x )} = 0

Use the basic trigonometric identity:

\frac{sin ( x )}{cos ( x )} = tan (x)

1 - 3 tan (x) = 0

1 - 3 tan (x) = 0

Move

1

to the right side

1 - 3 tan (x) = 0

Subtract

1

from both sides

1 - 3 tan (x) - 1 = 0 - 1

Simplify

- 3 tan (x) = - 1

- 3 tan (x) = - 1

Divide both sides by

- 3

- 3 tan (x) = - 1

Divide both sides by

- 3

\frac{- 3 tan ( x )}{- 3} = \frac{- 1}{- 3}

Simplify

\frac{- 3 tan ( x )}{- 3} = \frac{- 1}{- 3}

Simplify

\frac{- 3 tan ( x )}{- 3} : tan (x)

\frac{- 3 tan ( x )}{- 3}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{3 tan ( x )}{3}

Cancel the common factor:

3

= tan (x)

Simplify

\frac{- 1}{- 3} : \frac{3}{3}

\frac{- 1}{- 3}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{1}{3}

Rationalize

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{3}

= \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

tan (x) = \frac{3}{3}

General solutions for

tan (x) = \frac{3}{3}

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{6} + πn

x = \frac{π}{6} + πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{6} + πn

Graph

Popular Examples

cosh(x)=5

cosh (x) = 5

cosh(x)=7

cosh (x) = 7

4cos(x)-5=0

4 cos (x) - 5 = 0

e^{tan(x)}=2

e^{t a n (x)} = 2

tan^2(x)+4tan(x)-5=0

tan^{2} (x) + 4 tan (x) - 5 = 0

Frequently Asked Questions (FAQ)

What is the general solution for sin(2x)=2sqrt(3)sin^2(x) ?
The general solution for sin(2x)=2sqrt(3)sin^2(x) is x=2pin,x=pi+2pin,x= pi/6+pin